Algebraic Proofs

Algebraic Proofs

 

The various multiplication etc. devices shown in this book can be proved by arithmetical and geometrical methods, but here for brevity we give algebraic proofs.

 

Chapter 3

 

Examples

1-5   (ax + 5)² = a(a + 1)x² + 25    x =10

6-9   (ax + b)(ax + 10-b) = a(a + 1)x² + b(10 - b)   x=10

10    as above with x=100

 

Chapter 4

 

Examples

11-12   (ax + b)((10-a)x + b) = (a(10-a) + b)x²   x=10

 

Chapter 5

 

Examples

1-15   (x + a)(x + b) = x(x + a + b) +ab,   x=10n

Subtraction

Formula x to power of n (x-1) sum of (between x-1 and 1) x to power of r + x

Examples

16-19 (nx + a)(nx + b) = nx(nx + a + b) + ab

20-22 (x + a)(y + b) = (x + a)y + bx + ab, x=10m, y=10n

23-24 (x + a)(x + b)(x + c) = x²(x+a+b+c) + x(ab+ac+bc) + abc

25-26 (x + a)² = (x + 2a) + a²

27      (nx + a)² = n(nx + a)x + a²

28-29 (50 + a)² = 100(25 + a) + a²

30-31 a(xn - 1) = (a - 1)xn + (xn - a)

 

Chapter 6

 

(axn + bxn-1 + cxn-2 + . . . + zx0)(Axm + Bxm-1 + Cxm-2 + . . . + Zx0)

= aAxn+m + (aB+bA)xn+m-1 + (aC+bB+cA)xn+m-2 + . . . + zZ,   x=10

For grouping 2, 3 etc. figures on the right of the numbers x=10², 103 etc.

Division near a base. Since bx = (x - a)b + ab
therefore bx/(x-a)= b remainder ab. x=10, a < x

 

Chapter 7

 

(a + b)(a - b) = a² - b², where a = average, b < a

 

Chapter 8

 

(a + p)² = a² + p(2a + p)

(a + 3p)(a + 2p) - (a + p)a = p(a+3p + a+2p + a+p + a)

 

 

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